I'm looking for powertrain specs of the Gen3 Prius. I have a 2010 III that I tow with and am wondering how much hp and torque I lose when the HVB is dead. Max engine rpm? I've heard 112hp and 134hp. Then the electric motor only makes 20hp but is also 80hp and only brings the powertrain to 134hp, which doesn't math. Then there is no torque mentioned for the electric motor or combined torque. Which that one is the important one I'm trying to figure out. I'm looking at the wiki for it but don't know what to believe as there seems to be multiple sources and I think my manual even said 112hp. https://en.wikipedia.org/wiki/Toyota_Prius_(XW30) I was towing my boat again and this time around it just had no power on the highway. Noticed I only had 2 bars, while I normally have max or almost and it uses the gas primarily. It was about 20F hotter (about 81F) than the other times I've towed and was using the AC a little bit. Thanks, Higgins909
It does math, but to do the math you have to know how the car works. You have a 98 HP engine. You have an 80 HP electric motor, but where would that power be coming from? What doesn't come from the engine would have to come from the battery, but the battery can't give you 80 HP. And even if it could, you couldn't use all of it, because some of the engine's power is (virtually) always being carried electrically through the transmission and rejoining at the motor, so the capacity left for power from the battery will be 80 HP minus that. In practice, the limiting factor is the discharge control limit, a computed cap on the power the car is willing to suck from the battery. When that's around 36 HP, and you add it to the 98 HP from the engine, you get 134. The discharge limit is not always the same; it gets computed based on the battery charge, condition, temperature, etc. When the battery can't contribute, you lose those 36 HP. The electric motor by itself gives you 153 foot pounds, from zero RPM up to where that times the RPM equals its 80 HP power limit. From there up to higher RPMs, its max torque is 80 HP divided by the RPM. (I'm leaving out scale factors for units.) But that motor has a 58:22 reduction gear on it, so you multiply its raw torque by that, getting about 403 foot pounds, again up to the RPM where it starts to decline. Its RPM is directly related to road speed, so you could also think of that as 403 up to a certain road speed. To that you always add 78/108 of whatever torque the engine is producing at that moment. The engine can max out at 105 foot pounds at 4000 RPM. 78/108 of that is abut 76 foot pounds. So if your road speed is low enough to get the max motor torque, and the engine is at 4000 RPM giving its max torque, you get 403 + 76, or about 479 foot pounds ahead of the final drive. Your final drive ratio is about 3.268, so that's about 1565 foot pounds at the wheels.
